Solve this trigonometry inverse functions

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Solve this trigonometry inverse functions

Post  anderson_mark on Mon Jun 24, 2013 7:04 pm

Question: Evaluate sin-132,  arccos 22 and tan-1 (-1)


Last edited by anderson_mark on Mon Jun 24, 2013 7:06 pm; edited 1 time in total (Reason for editing : Need help)

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Re: Solve this trigonometry inverse functions

Post  shagydeep on Fri Jul 19, 2013 11:46 am

Hello,
sin(arccos(3/5))cos(arctan(7/13)) - cos(arccos(3/5))sin(arctan(7/13))
= (4/5)(13/√(218)) - (3/5)(7/√(218))
= [52/(5√(218))] - [21 / (5√(218))]
= 31 / 5√(218)
= 31√(218) / 1090 i guess this is your answer.
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